Solving Radical Inequalities
Worked solutions · Section 4.4, page 223 · Problems 37-52
Solving a radical inequality
\(n\) = index (the small number on the radical)
1. Isolate the radical
\(a\sqrt[n]{u} + c \le d \ \Rightarrow\ \sqrt[n]{u} \le \dfrac{d - c}{a}\)
Radical alone on one side before any power
2. Raise each side to the index
\(\left(\sqrt[n]{u}\right)^n = u\)
Same direction for a positive multiplier. Index 2: square. Index 3: cube
3. Negative multiplier flips the sign
\(-2v < 12 \ \Rightarrow\ v > -6\)
Dividing or multiplying by a negative reverses the inequality
4. Radicand of an even root
\(u \ge 0 \quad (n \text{ even})\)
No negative radicand under an even radical. Both conditions hold together
5. Odd index takes any radicand
\(\sqrt[3]{u} \ \text{defined for every} \ u\)
A cube root sets no second condition
6. Write the solution as a range
\(0 \le x < \dfrac{32}{49}\)
Lower bound from the radicand, upper bound from the inequality
Nonlinear systems
7. Substitution
\(y = x - 3 \ \Rightarrow\ \sqrt{x-3} = x - 3\)
One equation gives y; put it into the other
8. Zero-product property
\(ab = 0 \ \Rightarrow\ a = 0 \ \text{or}\ b = 0\)
Standard form first, then factor
9. Circle
\(x^2 + y^2 = r^2\)
Center at the origin, radius \(r\)
10. Check each point in both equations
\((2, 0):\ 2^2 + 0^2 = 4 \ \text{and}\ 0 = 2 - 2\)
A point must satisfy both equations
Problems 37-44: Solve the inequality.
Even index: keep the radicand nonnegative as a second condition
Problem 37
\(2\sqrt[3]{x} - 5 \ge 3\)
Rules used:
- 1. Isolate the radical
- 2. Raise each side to the index
- 5. Odd index takes any radicand
Step 1. Isolate the radical.
\(2\sqrt[3]{x} \ge 8\)
\(\sqrt[3]{x} \ge 4\)
Step 2. Cube each side.
\(x \ge 4^3\)
Step 3. Odd index, so no second condition.
A cube root is defined for every \(x\)
Solution
\(x \ge 64\)
Problem 38
\(\sqrt[3]{x-4} \le 5\)
Rules used:
- 2. Raise each side to the index
- 5. Odd index takes any radicand
Step 1. Cube each side.
\(x - 4 \le 5^3\)
\(x - 4 \le 125\)
Step 2. Add 4 to each side.
\(x \le 129\)
Solution
\(x \le 129\)
Problem 39
\(4\sqrt{x-2} > 20\)
Rules used:
- 1. Isolate the radical
- 2. Raise each side to the index
- 4. Radicand of an even root
- 6. Write the solution as a range
Step 1. Isolate the radical.
\(\sqrt{x-2} > 5\)
Step 2. Square each side.
\(x - 2 > 25\)
\(x > 27\)
Step 3. Check the radicand.
\(x - 2 \ge 0\)
\(x \ge 2\), already covered by \(x > 27\)
Solution
\(x > 27\)
Problem 40
\(7\sqrt{x+1} < 9\)
Rules used:
- 1. Isolate the radical
- 2. Raise each side to the index
- 4. Radicand of an even root
- 6. Write the solution as a range
Step 1. Isolate the radical.
\(\sqrt{x+1} < \dfrac{9}{7}\)
Step 2. Square each side.
\(x + 1 < \dfrac{81}{49}\)
\(x < \dfrac{32}{49}\)
Step 3. Check the radicand.
\(x + 1 \ge 0\)
\(x \ge -1\), which sets the lower bound
Solution
\(-1 \le x < \dfrac{32}{49}\)
Problem 41
\(2\sqrt{x} + 3 \le 8\)
Rules used:
- 1. Isolate the radical
- 2. Raise each side to the index
- 4. Radicand of an even root
- 6. Write the solution as a range
Step 1. Isolate the radical.
\(2\sqrt{x} \le 5\)
\(\sqrt{x} \le \dfrac{5}{2}\)
Step 2. Square each side.
\(x \le \dfrac{25}{4}\)
Step 3. Check the radicand.
\(x \ge 0\)
The lower bound
Solution
\(0 \le x \le \dfrac{25}{4}\)
Problem 42
\(\sqrt[3]{x+7} \ge 3\)
Rules used:
- 2. Raise each side to the index
- 5. Odd index takes any radicand
Step 1. Cube each side.
\(x + 7 \ge 27\)
Step 2. Subtract 7 from each side.
\(x \ge 20\)
Solution
\(x \ge 20\)
Problem 43
\(-2\sqrt[3]{x+4} < 12\)
Rules used:
- 1. Isolate the radical
- 3. Negative multiplier flips the sign
- 2. Raise each side to the index
- 5. Odd index takes any radicand
Step 1. Divide each side by -2 and flip the sign.
\(\sqrt[3]{x+4} > -6\)
Step 2. Cube each side.
\(x + 4 > -216\)
Step 3. Subtract 4 from each side.
\(x > -220\)
Solution
\(x > -220\)
Problem 44
\(-0.25\sqrt{x-6} \le -3\)
Rules used:
- 1. Isolate the radical
- 3. Negative multiplier flips the sign
- 2. Raise each side to the index
- 4. Radicand of an even root
Step 1. Divide each side by -0.25 and flip the sign.
\(\sqrt{x-6} \ge 12\)
Step 2. Square each side.
\(x - 6 \ge 144\)
\(x \ge 150\)
Step 3. Check the radicand.
\(x - 6 \ge 0\)
\(x \ge 6\), already covered
Solution
\(x \ge 150\)
Problems 45-46: Modeling with mathematics
Problem 45
\(\ell = 54d^{3/2}\)
Rules used:
- 1. Isolate the radical
- 2. Raise each side to the index
Step 1. Substitute 3 for the length.
\(3 = 54d^{3/2}\)
Step 2. Divide each side by 54.
\(d^{3/2} = \dfrac{1}{18}\)
Step 3. Raise each side to the two-thirds.
\(d = \left(\dfrac{1}{18}\right)^{2/3} \approx 0.15\)
Answer
\(d \approx 0.15\)
About 0.15 inch across
Problem 46
\(t = 0.5\sqrt{h}\)
Rules used:
- 1. Isolate the radical
- 2. Raise each side to the index
Step 1. Solve the model for the height.
\(\sqrt{h} = 2t\)
\(h = 4t^2\)
Step 2. Snowboarder, t = 1.21.
\(h = 4(1.21)^2 \approx 5.86\)
Step 3. Kangaroo, t = 0.81.
\(h = 4(0.81)^2 \approx 2.62\)
Step 4. Double each hang time.
\(h = 4(2.42)^2 \approx 23.43\)
\(h = 4(1.62)^2 \approx 10.50\)
Step 5. Compare.
Doubling \(t\) multiplies \(h\) by 4, since \(h = 4t^2\)
Answer
\(h = 4t^2\)
Snowboarder about 5.86 feet, kangaroo about 2.62 feet
Problems 47-52: Solve the nonlinear system. Justify your answer with a graph.
Problem 47
\(y = \sqrt{x-3},\ y = x - 3\)
Rules used:
- 7. Substitution
- 8. Zero-product property
- 10. Check each point in both equations
Step 1. Substitute for y.
\(\sqrt{x-3} = x - 3\)
Step 2. Square each side.
\(x - 3 = (x-3)^2\)
Step 3. Write in standard form and factor.
\(0 = (x-3)(x-4)\)
Step 4. Find each y.
\(x = 3\)
\(x = 4\)
\(y = 0\) and \(y = 1\)
Solutions
\((3, 0) \ \text{and}\ (4, 1)\)
Problem 48
\(y = \sqrt{4x+17},\ y = x + 5\)
Rules used:
- 7. Substitution
- 8. Zero-product property
- 10. Check each point in both equations
Step 1. Substitute for y and square each side.
\(4x + 17 = (x+5)^2\)
Step 2. Write in standard form and factor.
\(0 = x^2 + 6x + 8\)
\(0 = (x+2)(x+4)\)
Step 3. Find each y.
\(x = -2\)
\(x = -4\)
\(y = 3\) and \(y = 1\)
Solutions
\((-2, 3) \ \text{and}\ (-4, 1)\)
Problem 49
\(x^2 + y^2 = 4,\ y = x - 2\)
Rules used:
- 9. Circle
- 7. Substitution
- 8. Zero-product property
- 10. Check each point in both equations
Step 1. Substitute for y.
\(x^2 + (x-2)^2 = 4\)
Step 2. Expand and simplify.
\(2x^2 - 4x = 0\)
\((2x)(x - 2) = 0\)
Step 3. Find each y.
\(x = 0\)
\(x = 2\)
\(y = -2\) and \(y = 0\)
Solutions
\((0, -2) \ \text{and}\ (2, 0)\)
Problem 50
\(x^2 + y^2 = 25,\ y = -\dfrac{3}{4}x + \dfrac{25}{4}\)
Rules used:
- 9. Circle
- 7. Substitution
- 8. Zero-product property
- 10. Check each point in both equations
Step 1. Substitute for y.
\(x^2 + \left(-\dfrac{3}{4}x + \dfrac{25}{4}\right)^2 = 25\)
Step 2. Clear the fractions and simplify.
\(25x^2 - 150x + 225 = 0\)
\(x^2 - 6x + 9 = 0\)
Step 3. Factor.
\((x-3)^2 = 0\)
\(x = 3\)
Step 4. Find y.
\(y = 4\)
One point: the line touches the circle
Solution
\((3, 4)\)
Problem 51
\(x^2 + y^2 = 1,\ y = \dfrac{1}{2}x^2 - 1\)
Rules used:
- 9. Circle
- 7. Substitution
- 8. Zero-product property
- 10. Check each point in both equations
Step 1. Solve the second equation for x squared.
\(x^2 = 2y + 2\)
Step 2. Substitute into the circle.
\(2y + 2 + y^2 = 1\)
\(y^2 + 2y + 1 = 0\)
Step 3. Factor.
\((y+1)^2 = 0\)
\(y = -1\)
Step 4. Find x.
\(x^2 = 0\)
\(x = 0\)
Solution
\((0, -1)\)
Problem 52
\(x^2 + y^2 = 4,\ y^2 = x + 2\)
Rules used:
- 9. Circle
- 7. Substitution
- 8. Zero-product property
- 10. Check each point in both equations
Step 1. Substitute for y squared.
\(x^2 + x + 2 = 4\)
Step 2. Write in standard form and factor.
\(x^2 + x - 2 = 0\)
\((x+2)(x-1) = 0\)
Step 3. Find each y.
\(x = -2\)
\(x = 1\)
\(y = 0\); and \(y^2 = 3\), so \(y = \pm\sqrt{3}\)
Solutions
\((-2, 0),\ (1, \sqrt{3}),\ (1, -\sqrt{3})\)
Quick checklist
- Radical alone on one side? Isolate it before any power
- Multiplied or divided by a negative? Flip the inequality sign
- Even index? Radicand \(\ge 0\) is a second condition
- Odd index? No second condition
- Two conditions? Write the answer as one range
- Nonlinear system? Substitute, factor, then find every \(y\)
- Each point checked in both equations? The graph shows how many to expect